0=x^2-2x+1/2

Solution for 0=x^2-2x+1/2 equation:

0=x^2-2x+1/2

We move all terms to the left:

0-(x^2-2x+1/2)=0

We add all the numbers together, and all the variables

-(x^2-2x+1/2)=0

We get rid of parentheses

-x^2+2x-1/2=0

We multiply all the terms by the denominator


-x^2*2+2x*2-1=0

Wy multiply elements

-2x^2+4x-1=0

a = -2; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·(-2)·(-1)
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{2}}{2*-2}=\frac{-4-2\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{2}}{2*-2}=\frac{-4+2\sqrt{2}}{-4}
$